-2x=6((3x-29)/5)+18

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Solution for -2x=6((3x-29)/5)+18 equation: 



-2x=6((3x-29)/5)+18

We move all terms to the left:

-2x-(6((3x-29)/5)+18)=0

We multiply all the terms by the denominator


-2x*5)+18)-(6((3x-29)=0

Wy multiply elements

-10x^2=0

a = -10; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-10)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-20}=0$

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