-2y(5y+1)-y=-4(y-3)

Solution for -2y(5y+1)-y=-4(y-3) equation:

-2y(5y+1)-y=-4(y-3)

We move all terms to the left:

-2y(5y+1)-y-(-4(y-3))=0

We add all the numbers together, and all the variables

-1y-2y(5y+1)-(-4(y-3))=0

We multiply parentheses

-10y^2-1y-2y-(-4(y-3))=0


We calculate terms in parentheses: -(-4(y-3)), so:

-4(y-3)

We multiply parentheses

-4y+12

Back to the equation:

-(-4y+12)


We add all the numbers together, and all the variables

-10y^2-3y-(-4y+12)=0

We get rid of parentheses

-10y^2-3y+4y-12=0

We add all the numbers together, and all the variables

-10y^2+y-12=0

a = -10; b = 1; c = -12;
Δ = b2-4ac
Δ = 12-4·(-10)·(-12)
Δ = -479
Delta is less than zero, so there is no solution for the equation