-2y(5y-10)-y=-3(y-5)

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Solution for -2y(5y-10)-y=-3(y-5) equation:



-2y(5y-10)-y=-3(y-5)
We move all terms to the left:
-2y(5y-10)-y-(-3(y-5))=0
We add all the numbers together, and all the variables
-1y-2y(5y-10)-(-3(y-5))=0
We multiply parentheses
-10y^2-1y+20y-(-3(y-5))=0
We calculate terms in parentheses: -(-3(y-5)), so:
-3(y-5)
We multiply parentheses
-3y+15
Back to the equation:
-(-3y+15)
We add all the numbers together, and all the variables
-10y^2+19y-(-3y+15)=0
We get rid of parentheses
-10y^2+19y+3y-15=0
We add all the numbers together, and all the variables
-10y^2+22y-15=0
a = -10; b = 22; c = -15;
Δ = b2-4ac
Δ = 222-4·(-10)·(-15)
Δ = -116
Delta is less than zero, so there is no solution for the equation

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