-2y(y+2)+7=3(y+6)

Solution for -2y(y+2)+7=3(y+6) equation:

-2y(y+2)+7=3(y+6)

We move all terms to the left:

-2y(y+2)+7-(3(y+6))=0

We multiply parentheses

-2y^2-4y-(3(y+6))+7=0


We calculate terms in parentheses: -(3(y+6)), so:

3(y+6)

We multiply parentheses

3y+18

Back to the equation:

-(3y+18)


We get rid of parentheses

-2y^2-4y-3y-18+7=0

We add all the numbers together, and all the variables

-2y^2-7y-11=0

a = -2; b = -7; c = -11;
Δ = b2-4ac
Δ = -72-4·(-2)·(-11)
Δ = -39
Delta is less than zero, so there is no solution for the equation