If it's not what You are looking for type in the equation solver your own equation and let us solve it.
-2y+12=2(y+4)
We move all terms to the left:
-2y+12-(2(y+4))=0
We calculate terms in parentheses: -(2(y+4)), so:We get rid of parentheses
2(y+4)
We multiply parentheses
2y+8
Back to the equation:
-(2y+8)
-2y-2y-8+12=0
We add all the numbers together, and all the variables
-4y+4=0
We move all terms containing y to the left, all other terms to the right
-4y=-4
y=-4/-4
y=1
| 54=3*(4+x2) | | f+18-20=25 | | 2(3y-4)-5=7y+25-(4y+8 | | -108+12x=32+5x | | 8=3(n-6)+2 | | p-(-2p-5)=25 | | -3(u+1)=7u+27 | | -7r=6-8r | | 21s=1,575 | | 3(b-7)-2=4 | | 5x+2x-2+15-8+3x-20=5x | | 2t=816 | | 3x-12=7x8 | | 22=w/13 | | 3(h+5)-8=1 | | n/0.8=64 | | 31v=744 | | 4(x +3)=17 | | 1/4(4+8x)=1/2(6-4x) | | 25=t/29 | | 7x-10=8+5 | | x-102=22 | | 0.9x-21=0.9=0.2(5-x) | | 25=t/19 | | 670=c2 | | -24=-8w+4(w+3) | | 19=m/18 | | –10+7f=9f+10 | | v÷73=13 | | 3x^2+9x+1= | | 3(x-4))=-3 | | (b+3/2)=3 |