-2y+28=2(y-2)

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Solution for -2y+28=2(y-2) equation: 



-2y+28=2(y-2)

We move all terms to the left:

-2y+28-(2(y-2))=0



We calculate terms in parentheses: -(2(y-2)), so:

2(y-2)

We multiply parentheses

2y-4

Back to the equation:

-(2y-4)



We get rid of parentheses

-2y-2y+4+28=0

We add all the numbers together, and all the variables

-4y+32=0

We move all terms containing y to the left, all other terms to the right

-4y=-32

y=-32/-4

y=+8

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