-2y+3(-8y-2)=3-8(5-y)

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Solution for -2y+3(-8y-2)=3-8(5-y) equation: 



-2y+3(-8y-2)=3-8(5-y)

We move all terms to the left:

-2y+3(-8y-2)-(3-8(5-y))=0

We add all the numbers together, and all the variables

-2y+3(-8y-2)-(3-8(-1y+5))=0

We multiply parentheses

-2y-24y-(3-8(-1y+5))-6=0



We calculate terms in parentheses: -(3-8(-1y+5)), so:

3-8(-1y+5)

determiningTheFunctionDomain
-8(-1y+5)+3

We multiply parentheses

8y-40+3

We add all the numbers together, and all the variables

8y-37

Back to the equation:

-(8y-37)



We add all the numbers together, and all the variables

-26y-(8y-37)-6=0

We get rid of parentheses

-26y-8y+37-6=0

We add all the numbers together, and all the variables

-34y+31=0

We move all terms containing y to the left, all other terms to the right

-34y=-31

y=-31/-34

y=31/34

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