-2y+32=4(y-4)

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Solution for -2y+32=4(y-4) equation:



-2y+32=4(y-4)
We move all terms to the left:
-2y+32-(4(y-4))=0
We calculate terms in parentheses: -(4(y-4)), so:
4(y-4)
We multiply parentheses
4y-16
Back to the equation:
-(4y-16)
We get rid of parentheses
-2y-4y+16+32=0
We add all the numbers together, and all the variables
-6y+48=0
We move all terms containing y to the left, all other terms to the right
-6y=-48
y=-48/-6
y=+8

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