-2y+4(y-3)=-32

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Solution for -2y+4(y-3)=-32 equation: 



-2y+4(y-3)=-32

We move all terms to the left:

-2y+4(y-3)-(-32)=0

We add all the numbers together, and all the variables

-2y+4(y-3)+32=0

We multiply parentheses

-2y+4y-12+32=0

We add all the numbers together, and all the variables

2y+20=0

We move all terms containing y to the left, all other terms to the right

2y=-20

y=-20/2

y=-10

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