-2y+6-(4y-7)=3(-y+10)-2(2y-5)-(-y+27)

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Solution for -2y+6-(4y-7)=3(-y+10)-2(2y-5)-(-y+27) equation: 



-2y+6-(4y-7)=3(-y+10)-2(2y-5)-(-y+27)

We move all terms to the left:

-2y+6-(4y-7)-(3(-y+10)-2(2y-5)-(-y+27))=0

We add all the numbers together, and all the variables

-2y-(4y-7)-(3(-1y+10)-2(2y-5)-(-1y+27))+6=0

We get rid of parentheses

-2y-4y-(3(-1y+10)-2(2y-5)-(-1y+27))+7+6=0



We calculate terms in parentheses: -(3(-1y+10)-2(2y-5)-(-1y+27)), so:

3(-1y+10)-2(2y-5)-(-1y+27)

We multiply parentheses

-3y-4y-(-1y+27)+30+10

We get rid of parentheses

-3y-4y+1y-27+30+10

We add all the numbers together, and all the variables

-6y+13

Back to the equation:

-(-6y+13)



We add all the numbers together, and all the variables

-6y-(-6y+13)+13=0

We get rid of parentheses

-6y+6y-13+13=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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