-2y+7(1y-3)=8+6(-2-y)

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Solution for -2y+7(1y-3)=8+6(-2-y) equation: 



-2y+7(1y-3)=8+6(-2-y)

We move all terms to the left:

-2y+7(1y-3)-(8+6(-2-y))=0

We add all the numbers together, and all the variables

-2y+7(y-3)-(8+6(-1y-2))=0

We multiply parentheses

-2y+7y-(8+6(-1y-2))-21=0



We calculate terms in parentheses: -(8+6(-1y-2)), so:

8+6(-1y-2)

determiningTheFunctionDomain
6(-1y-2)+8

We multiply parentheses

-6y-12+8

We add all the numbers together, and all the variables

-6y-4

Back to the equation:

-(-6y-4)



We add all the numbers together, and all the variables

5y-(-6y-4)-21=0

We get rid of parentheses

5y+6y+4-21=0

We add all the numbers together, and all the variables

11y-17=0

We move all terms containing y to the left, all other terms to the right

11y=17

y=17/11

y=1+6/11

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