-2y-3(y-2)=3(y+10)

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Solution for -2y-3(y-2)=3(y+10) equation: 



-2y-3(y-2)=3(y+10)

We move all terms to the left:

-2y-3(y-2)-(3(y+10))=0

We multiply parentheses

-2y-3y-(3(y+10))+6=0



We calculate terms in parentheses: -(3(y+10)), so:

3(y+10)

We multiply parentheses

3y+30

Back to the equation:

-(3y+30)



We add all the numbers together, and all the variables

-5y-(3y+30)+6=0

We get rid of parentheses

-5y-3y-30+6=0

We add all the numbers together, and all the variables

-8y-24=0

We move all terms containing y to the left, all other terms to the right

-8y=24

y=24/-8

y=-3

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