-2y-3-(-4y+5+(-y+2-(3y-1)+y-5))=-(y-4)

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Solution for -2y-3-(-4y+5+(-y+2-(3y-1)+y-5))=-(y-4) equation: 



-2y-3-(-4y+5+(-y+2-(3y-1)+y-5))=-(y-4)

We move all terms to the left:

-2y-3-(-4y+5+(-y+2-(3y-1)+y-5))-(-(y-4))=0



We calculate terms in parentheses: -(-4y+5+(-y+2-(3y-1)+y-5)), so:

-4y+5+(-y+2-(3y-1)+y-5)

determiningTheFunctionDomain
-4y+(-y+2-(3y-1)+y-5)+5



We calculate terms in parentheses: +(-y+2-(3y-1)+y-5), so:

-y+2-(3y-1)+y-5

determiningTheFunctionDomain
-y-(3y-1)+y+2-5

We add all the numbers together, and all the variables

-(3y-1)-3

We get rid of parentheses

-3y+1-3

We add all the numbers together, and all the variables

-3y-2

Back to the equation:

+(-3y-2)



We get rid of parentheses

-4y-3y-2+5

We add all the numbers together, and all the variables

-7y+3

Back to the equation:

-(-7y+3)





We calculate terms in parentheses: -(-(y-4)), so:

-(y-4)

We get rid of parentheses

-y+4

We add all the numbers together, and all the variables

-1y+4

Back to the equation:

-(-1y+4)



We get rid of parentheses

-2y+7y+1y-3-4-3=0

We add all the numbers together, and all the variables

6y-10=0

We move all terms containing y to the left, all other terms to the right

6y=10

y=10/6

y=1+2/3

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