-2y-5(-8y-4)=7+3(-8-y)

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Solution for -2y-5(-8y-4)=7+3(-8-y) equation: 



-2y-5(-8y-4)=7+3(-8-y)

We move all terms to the left:

-2y-5(-8y-4)-(7+3(-8-y))=0

We add all the numbers together, and all the variables

-2y-5(-8y-4)-(7+3(-1y-8))=0

We multiply parentheses

-2y+40y-(7+3(-1y-8))+20=0



We calculate terms in parentheses: -(7+3(-1y-8)), so:

7+3(-1y-8)

determiningTheFunctionDomain
3(-1y-8)+7

We multiply parentheses

-3y-24+7

We add all the numbers together, and all the variables

-3y-17

Back to the equation:

-(-3y-17)



We add all the numbers together, and all the variables

38y-(-3y-17)+20=0

We get rid of parentheses

38y+3y+17+20=0

We add all the numbers together, and all the variables

41y+37=0

We move all terms containing y to the left, all other terms to the right

41y=-37

y=-37/41

y=-37/41

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