-2y2+24y-72=0

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Solution for -2y2+24y-72=0 equation: 



-2y^2+24y-72=0

a = -2; b = 24; c = -72;
Δ = b2-4ac
Δ = 242-4·(-2)·(-72)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{-24}{-4}=+6$

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