-2y2=8-8y

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Solution for -2y2=8-8y equation: 



-2y^2=8-8y

We move all terms to the left:

-2y^2-(8-8y)=0

We add all the numbers together, and all the variables

-2y^2-(-8y+8)=0

We get rid of parentheses

-2y^2+8y-8=0

a = -2; b = 8; c = -8;
Δ = b2-4ac
Δ = 82-4·(-2)·(-8)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{-8}{-4}=+2$

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