-2z+-4(6z-5)=-67+3z

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Solution for -2z+-4(6z-5)=-67+3z equation: 



-2z+-4(6z-5)=-67+3z

We move all terms to the left:

-2z+-4(6z-5)-(-67+3z)=0

We add all the numbers together, and all the variables

-2z-4(6z-5)-(3z-67)+=0

We add all the numbers together, and all the variables

-2z-4(6z-5)-(3z-67)=0

We multiply parentheses

-2z-24z-(3z-67)+20=0

We get rid of parentheses

-2z-24z-3z+67+20=0

We add all the numbers together, and all the variables

-29z+87=0

We move all terms containing z to the left, all other terms to the right

-29z=-87

z=-87/-29

z=+3

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