-2z+12=-2(z-6)

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Solution for -2z+12=-2(z-6) equation: 



-2z+12=-2(z-6)

We move all terms to the left:

-2z+12-(-2(z-6))=0



We calculate terms in parentheses: -(-2(z-6)), so:

-2(z-6)

We multiply parentheses

-2z+12

Back to the equation:

-(-2z+12)



We get rid of parentheses

-2z+2z-12+12=0

We add all the numbers together, and all the variables

=0

z=0/1

z=0

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