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-2z+3=-3z^2
We move all terms to the left:
-2z+3-(-3z^2)=0
We get rid of parentheses
3z^2-2z+3=0
a = 3; b = -2; c = +3;
Δ = b2-4ac
Δ = -22-4·3·3
Δ = -32
Delta is less than zero, so there is no solution for the equation
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