-2z-5(-1z-5)=-3+4(9-z)

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Solution for -2z-5(-1z-5)=-3+4(9-z) equation: 



-2z-5(-1z-5)=-3+4(9-z)

We move all terms to the left:

-2z-5(-1z-5)-(-3+4(9-z))=0

We add all the numbers together, and all the variables

-2z-5(-1z-5)-(-3+4(-1z+9))=0

We multiply parentheses

-2z+5z-(-3+4(-1z+9))+25=0



We calculate terms in parentheses: -(-3+4(-1z+9)), so:

-3+4(-1z+9)

determiningTheFunctionDomain
4(-1z+9)-3

We multiply parentheses

-4z+36-3

We add all the numbers together, and all the variables

-4z+33

Back to the equation:

-(-4z+33)



We add all the numbers together, and all the variables

3z-(-4z+33)+25=0

We get rid of parentheses

3z+4z-33+25=0

We add all the numbers together, and all the variables

7z-8=0

We move all terms containing z to the left, all other terms to the right

7z=8

z=8/7

z=1+1/7

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