-3((6y+15)/3)+4y=-13

Solution for -3((6y+15)/3)+4y=-13 equation:

-3((6y+15)/3)+4y=-13

We move all terms to the left:

-3((6y+15)/3)+4y-(-13)=0

We add all the numbers together, and all the variables

4y-3((6y+15)/3)+13=0

We multiply all the terms by the denominator


4y*3)-3((6y+15)+13*3)=0

We add all the numbers together, and all the variables

4y*3)-3((6y+15)=0

Wy multiply elements

12y^2=0

a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{24}=0$