-3(-20q-15)+6=11q+2

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Solution for -3(-20q-15)+6=11q+2 equation: 



-3(-20q-15)+6=11q+2

We move all terms to the left:

-3(-20q-15)+6-(11q+2)=0

We multiply parentheses

60q-(11q+2)+45+6=0

We get rid of parentheses

60q-11q-2+45+6=0

We add all the numbers together, and all the variables

49q+49=0

We move all terms containing q to the left, all other terms to the right

49q=-49

q=-49/49

q=-1

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