-3(-2r+2)-(2r+2)=12

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Solution for -3(-2r+2)-(2r+2)=12 equation: 



-3(-2r+2)-(2r+2)=12

We move all terms to the left:

-3(-2r+2)-(2r+2)-(12)=0

We multiply parentheses

6r-(2r+2)-6-12=0

We get rid of parentheses

6r-2r-2-6-12=0

We add all the numbers together, and all the variables

4r-20=0

We move all terms containing r to the left, all other terms to the right

4r=20

r=20/4

r=5

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