-3(-2u+2)-8u=2(u-2)-8

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Solution for -3(-2u+2)-8u=2(u-2)-8 equation: 



-3(-2u+2)-8u=2(u-2)-8

We move all terms to the left:

-3(-2u+2)-8u-(2(u-2)-8)=0

We add all the numbers together, and all the variables

-8u-3(-2u+2)-(2(u-2)-8)=0

We multiply parentheses

-8u+6u-(2(u-2)-8)-6=0



We calculate terms in parentheses: -(2(u-2)-8), so:

2(u-2)-8

We multiply parentheses

2u-4-8

We add all the numbers together, and all the variables

2u-12

Back to the equation:

-(2u-12)



We add all the numbers together, and all the variables

-2u-(2u-12)-6=0

We get rid of parentheses

-2u-2u+12-6=0

We add all the numbers together, and all the variables

-4u+6=0

We move all terms containing u to the left, all other terms to the right

-4u=-6

u=-6/-4

u=1+1/2

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