-3(-2x-4)=-5x(-3x+6)

Solution for -3(-2x-4)=-5x(-3x+6) equation:

-3(-2x-4)=-5x(-3x+6)

We move all terms to the left:

-3(-2x-4)-(-5x(-3x+6))=0

We multiply parentheses

6x-(-5x(-3x+6))+12=0


We calculate terms in parentheses: -(-5x(-3x+6)), so:

-5x(-3x+6)

We multiply parentheses

15x^2-30x

Back to the equation:

-(15x^2-30x)


We get rid of parentheses

-15x^2+6x+30x+12=0

We add all the numbers together, and all the variables

-15x^2+36x+12=0

a = -15; b = 36; c = +12;
Δ = b2-4ac
Δ = 362-4·(-15)·12
Δ = 2016
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2016}=\sqrt{144*14}=\sqrt{144}*\sqrt{14}=12\sqrt{14}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-12\sqrt{14}}{2*-15}=\frac{-36-12\sqrt{14}}{-30}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+12\sqrt{14}}{2*-15}=\frac{-36+12\sqrt{14}}{-30}
$