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-3(-2x-5)=-5(3x+5)+5/4
We move all terms to the left:
-3(-2x-5)-(-5(3x+5)+5/4)=0
We multiply parentheses
6x-(-5(3x+5)+5/4)+15=0
We multiply all the terms by the denominator
6x*4)-(-5(3x+5)+5+15*4)=0
We add all the numbers together, and all the variables
6x*4)-(-5(3x+5)=0
We multiply parentheses
6x*4)-(-15x-25=0
Wy multiply elements
24x^2-15x-25=0
a = 24; b = -15; c = -25;
Δ = b2-4ac
Δ = -152-4·24·(-25)
Δ = 2625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2625}=\sqrt{25*105}=\sqrt{25}*\sqrt{105}=5\sqrt{105}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-5\sqrt{105}}{2*24}=\frac{15-5\sqrt{105}}{48} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+5\sqrt{105}}{2*24}=\frac{15+5\sqrt{105}}{48} $
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