-3(-3u+4)-u=4(u-4)-2

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Solution for -3(-3u+4)-u=4(u-4)-2 equation: 



-3(-3u+4)-u=4(u-4)-2

We move all terms to the left:

-3(-3u+4)-u-(4(u-4)-2)=0

We add all the numbers together, and all the variables

-1u-3(-3u+4)-(4(u-4)-2)=0

We multiply parentheses

-1u+9u-(4(u-4)-2)-12=0



We calculate terms in parentheses: -(4(u-4)-2), so:

4(u-4)-2

We multiply parentheses

4u-16-2

We add all the numbers together, and all the variables

4u-18

Back to the equation:

-(4u-18)



We add all the numbers together, and all the variables

8u-(4u-18)-12=0

We get rid of parentheses

8u-4u+18-12=0

We add all the numbers together, and all the variables

4u+6=0

We move all terms containing u to the left, all other terms to the right

4u=-6

u=-6/4

u=-1+1/2

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