-3(-3u+4)-u=4(u-4)-6

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Solution for -3(-3u+4)-u=4(u-4)-6 equation: 



-3(-3u+4)-u=4(u-4)-6

We move all terms to the left:

-3(-3u+4)-u-(4(u-4)-6)=0

We add all the numbers together, and all the variables

-1u-3(-3u+4)-(4(u-4)-6)=0

We multiply parentheses

-1u+9u-(4(u-4)-6)-12=0



We calculate terms in parentheses: -(4(u-4)-6), so:

4(u-4)-6

We multiply parentheses

4u-16-6

We add all the numbers together, and all the variables

4u-22

Back to the equation:

-(4u-22)



We add all the numbers together, and all the variables

8u-(4u-22)-12=0

We get rid of parentheses

8u-4u+22-12=0

We add all the numbers together, and all the variables

4u+10=0

We move all terms containing u to the left, all other terms to the right

4u=-10

u=-10/4

u=-2+1/2

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