-3(-3x-4)=-7(x+5)+47+16x

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Solution for -3(-3x-4)=-7(x+5)+47+16x equation: 



-3(-3x-4)=-7(x+5)+47+16x

We move all terms to the left:

-3(-3x-4)-(-7(x+5)+47+16x)=0

We multiply parentheses

9x-(-7(x+5)+47+16x)+12=0



We calculate terms in parentheses: -(-7(x+5)+47+16x), so:

-7(x+5)+47+16x

determiningTheFunctionDomain
-7(x+5)+16x+47

We add all the numbers together, and all the variables

16x-7(x+5)+47

We multiply parentheses

16x-7x-35+47

We add all the numbers together, and all the variables

9x+12

Back to the equation:

-(9x+12)



We get rid of parentheses

9x-9x-12+12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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