-3(-3y+7)-3y=2(y-3)-9

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Solution for -3(-3y+7)-3y=2(y-3)-9 equation: 



-3(-3y+7)-3y=2(y-3)-9

We move all terms to the left:

-3(-3y+7)-3y-(2(y-3)-9)=0

We add all the numbers together, and all the variables

-3y-3(-3y+7)-(2(y-3)-9)=0

We multiply parentheses

-3y+9y-(2(y-3)-9)-21=0



We calculate terms in parentheses: -(2(y-3)-9), so:

2(y-3)-9

We multiply parentheses

2y-6-9

We add all the numbers together, and all the variables

2y-15

Back to the equation:

-(2y-15)



We add all the numbers together, and all the variables

6y-(2y-15)-21=0

We get rid of parentheses

6y-2y+15-21=0

We add all the numbers together, and all the variables

4y-6=0

We move all terms containing y to the left, all other terms to the right

4y=6

y=6/4

y=1+1/2

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