-3(-3y+9)-8y=7(y-3)-4

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Solution for -3(-3y+9)-8y=7(y-3)-4 equation: 



-3(-3y+9)-8y=7(y-3)-4

We move all terms to the left:

-3(-3y+9)-8y-(7(y-3)-4)=0

We add all the numbers together, and all the variables

-8y-3(-3y+9)-(7(y-3)-4)=0

We multiply parentheses

-8y+9y-(7(y-3)-4)-27=0



We calculate terms in parentheses: -(7(y-3)-4), so:

7(y-3)-4

We multiply parentheses

7y-21-4

We add all the numbers together, and all the variables

7y-25

Back to the equation:

-(7y-25)



We add all the numbers together, and all the variables

y-(7y-25)-27=0

We get rid of parentheses

y-7y+25-27=0

We add all the numbers together, and all the variables

-6y-2=0

We move all terms containing y to the left, all other terms to the right

-6y=2

y=2/-6

y=-1/3

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