-3(-4-b)=5+(16b/3)

Solution for -3(-4-b)=5+(16b/3) equation:

-3(-4-b)=5+(16b/3)

We move all terms to the left:

-3(-4-b)-(5+(16b/3))=0

We add all the numbers together, and all the variables

-3(-1b-4)-(5+(+16b/3))=0

We multiply parentheses

3b-(5+(+16b/3))+12=0

We multiply all the terms by the denominator


3b*3))-(5+(+16b+12*3))=0

We add all the numbers together, and all the variables

3b*3))-(5+(16b+36))=0

We add all the numbers together, and all the variables

3b*3))-(5+(16b=0

Wy multiply elements

9b^2=0

a = 9; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·9·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$b=\frac{-b}{2a}=\frac{0}{18}=0$