-3(-4-b)=5-4/b

Solution for -3(-4-b)=5-4/b equation:

-3(-4-b)=5-4/b

We move all terms to the left:

-3(-4-b)-(5-4/b)=0


Domain of the equation: b)!=0

b!=0/1

b!=0

b∈R


We add all the numbers together, and all the variables

-3(-1b-4)-(-4/b+5)=0

We multiply parentheses

3b-(-4/b+5)+12=0

We get rid of parentheses

3b+4/b-5+12=0

We multiply all the terms by the denominator


3b*b-5*b+12*b+4=0

We add all the numbers together, and all the variables

7b+3b*b+4=0

Wy multiply elements

3b^2+7b+4=0

a = 3; b = 7; c = +4;
Δ = b2-4ac
Δ = 72-4·3·4
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-1}{2*3}=\frac{-8}{6}
=-1+1/3
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+1}{2*3}=\frac{-6}{6}
=-1
$