-3(-4u+5)-4u=2(u-3)-6

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Solution for -3(-4u+5)-4u=2(u-3)-6 equation: 



-3(-4u+5)-4u=2(u-3)-6

We move all terms to the left:

-3(-4u+5)-4u-(2(u-3)-6)=0

We add all the numbers together, and all the variables

-4u-3(-4u+5)-(2(u-3)-6)=0

We multiply parentheses

-4u+12u-(2(u-3)-6)-15=0



We calculate terms in parentheses: -(2(u-3)-6), so:

2(u-3)-6

We multiply parentheses

2u-6-6

We add all the numbers together, and all the variables

2u-12

Back to the equation:

-(2u-12)



We add all the numbers together, and all the variables

8u-(2u-12)-15=0

We get rid of parentheses

8u-2u+12-15=0

We add all the numbers together, and all the variables

6u-3=0

We move all terms containing u to the left, all other terms to the right

6u=3

u=3/6

u=1/2

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