-3(-4u+6-2u)=4(u-3)

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Solution for -3(-4u+6-2u)=4(u-3) equation: 



-3(-4u+6-2u)=4(u-3)

We move all terms to the left:

-3(-4u+6-2u)-(4(u-3))=0

We add all the numbers together, and all the variables

-3(-6u+6)-(4(u-3))=0

We multiply parentheses

18u-(4(u-3))-18=0



We calculate terms in parentheses: -(4(u-3)), so:

4(u-3)

We multiply parentheses

4u-12

Back to the equation:

-(4u-12)



We get rid of parentheses

18u-4u+12-18=0

We add all the numbers together, and all the variables

14u-6=0

We move all terms containing u to the left, all other terms to the right

14u=6

u=6/14

u=3/7

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