-3(-5y-2)+3(-5y+2)=4(y+4)

Solution for -3(-5y-2)+3(-5y+2)=4(y+4) equation:

-3(-5y-2)+3(-5y+2)=4(y+4)

We move all terms to the left:

-3(-5y-2)+3(-5y+2)-(4(y+4))=0

We multiply parentheses

15y-15y-(4(y+4))+6+6=0


We calculate terms in parentheses: -(4(y+4)), so:

4(y+4)

We multiply parentheses

4y+16

Back to the equation:

-(4y+16)


We add all the numbers together, and all the variables

-(4y+16)+12=0

We get rid of parentheses

-4y-16+12=0

We add all the numbers together, and all the variables

-4y-4=0

We move all terms containing y to the left, all other terms to the right

-4y=4

y=4/-4

y=-1