-3(-5y-2)+3(-5y+2)=4(y+4)

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Solution for -3(-5y-2)+3(-5y+2)=4(y+4) equation:



-3(-5y-2)+3(-5y+2)=4(y+4)
We move all terms to the left:
-3(-5y-2)+3(-5y+2)-(4(y+4))=0
We multiply parentheses
15y-15y-(4(y+4))+6+6=0
We calculate terms in parentheses: -(4(y+4)), so:
4(y+4)
We multiply parentheses
4y+16
Back to the equation:
-(4y+16)
We add all the numbers together, and all the variables
-(4y+16)+12=0
We get rid of parentheses
-4y-16+12=0
We add all the numbers together, and all the variables
-4y-4=0
We move all terms containing y to the left, all other terms to the right
-4y=4
y=4/-4
y=-1

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