-3(-6)=3(x+4)+8(2x+x)

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Solution for -3(-6)=3(x+4)+8(2x+x) equation:



-3(-6)=3(x+4)+8(2x+x)
We move all terms to the left:
-3(-6)-(3(x+4)+8(2x+x))=0
We add all the numbers together, and all the variables
-(3(x+4)+8(+3x))-3(-6)=0
We add all the numbers together, and all the variables
-(3(x+4)+8(+3x))+18=0
We calculate terms in parentheses: -(3(x+4)+8(+3x)), so:
3(x+4)+8(+3x)
We multiply parentheses
3x+24x+12
We add all the numbers together, and all the variables
27x+12
Back to the equation:
-(27x+12)
We get rid of parentheses
-27x-12+18=0
We add all the numbers together, and all the variables
-27x+6=0
We move all terms containing x to the left, all other terms to the right
-27x=-6
x=-6/-27
x=2/9

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