-3(-6-b)=1/3(b+38)

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Solution for -3(-6-b)=1/3(b+38) equation: 



-3(-6-b)=1/3(b+38)

We move all terms to the left:

-3(-6-b)-(1/3(b+38))=0



Domain of the equation: 3(b+38))!=0

b∈R



We add all the numbers together, and all the variables

-3(-1b-6)-(1/3(b+38))=0

We multiply parentheses

3b-(1/3(b+38))+18=0

We multiply all the terms by the denominator


3b*3(b+38))-(1+18*3(b+38))=0

Wy multiply elements

9b^2(b+54b(b=0

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