-3(-6u+4)-6u=2(u-5)-4

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Solution for -3(-6u+4)-6u=2(u-5)-4 equation: 



-3(-6u+4)-6u=2(u-5)-4

We move all terms to the left:

-3(-6u+4)-6u-(2(u-5)-4)=0

We add all the numbers together, and all the variables

-6u-3(-6u+4)-(2(u-5)-4)=0

We multiply parentheses

-6u+18u-(2(u-5)-4)-12=0



We calculate terms in parentheses: -(2(u-5)-4), so:

2(u-5)-4

We multiply parentheses

2u-10-4

We add all the numbers together, and all the variables

2u-14

Back to the equation:

-(2u-14)



We add all the numbers together, and all the variables

12u-(2u-14)-12=0

We get rid of parentheses

12u-2u+14-12=0

We add all the numbers together, and all the variables

10u+2=0

We move all terms containing u to the left, all other terms to the right

10u=-2

u=-2/10

u=-1/5

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