-3(-6u+4)-6u=2(u-5)-4

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Solution for -3(-6u+4)-6u=2(u-5)-4 equation:



-3(-6u+4)-6u=2(u-5)-4
We move all terms to the left:
-3(-6u+4)-6u-(2(u-5)-4)=0
We add all the numbers together, and all the variables
-6u-3(-6u+4)-(2(u-5)-4)=0
We multiply parentheses
-6u+18u-(2(u-5)-4)-12=0
We calculate terms in parentheses: -(2(u-5)-4), so:
2(u-5)-4
We multiply parentheses
2u-10-4
We add all the numbers together, and all the variables
2u-14
Back to the equation:
-(2u-14)
We add all the numbers together, and all the variables
12u-(2u-14)-12=0
We get rid of parentheses
12u-2u+14-12=0
We add all the numbers together, and all the variables
10u+2=0
We move all terms containing u to the left, all other terms to the right
10u=-2
u=-2/10
u=-1/5

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