-3(-6x+1)-6x=2(x-4)-7

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Solution for -3(-6x+1)-6x=2(x-4)-7 equation: 



-3(-6x+1)-6x=2(x-4)-7

We move all terms to the left:

-3(-6x+1)-6x-(2(x-4)-7)=0

We add all the numbers together, and all the variables

-6x-3(-6x+1)-(2(x-4)-7)=0

We multiply parentheses

-6x+18x-(2(x-4)-7)-3=0



We calculate terms in parentheses: -(2(x-4)-7), so:

2(x-4)-7

We multiply parentheses

2x-8-7

We add all the numbers together, and all the variables

2x-15

Back to the equation:

-(2x-15)



We add all the numbers together, and all the variables

12x-(2x-15)-3=0

We get rid of parentheses

12x-2x+15-3=0

We add all the numbers together, and all the variables

10x+12=0

We move all terms containing x to the left, all other terms to the right

10x=-12

x=-12/10

x=-1+1/5

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