-3(-6y+2)-y=2(y-5)-6

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Solution for -3(-6y+2)-y=2(y-5)-6 equation: 



-3(-6y+2)-y=2(y-5)-6

We move all terms to the left:

-3(-6y+2)-y-(2(y-5)-6)=0

We add all the numbers together, and all the variables

-1y-3(-6y+2)-(2(y-5)-6)=0

We multiply parentheses

-1y+18y-(2(y-5)-6)-6=0



We calculate terms in parentheses: -(2(y-5)-6), so:

2(y-5)-6

We multiply parentheses

2y-10-6

We add all the numbers together, and all the variables

2y-16

Back to the equation:

-(2y-16)



We add all the numbers together, and all the variables

17y-(2y-16)-6=0

We get rid of parentheses

17y-2y+16-6=0

We add all the numbers together, and all the variables

15y+10=0

We move all terms containing y to the left, all other terms to the right

15y=-10

y=-10/15

y=-2/3

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