-3(-7+2)-3u=6(u-3)-4

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Solution for -3(-7+2)-3u=6(u-3)-4 equation: 



-3(-7+2)-3u=6(u-3)-4

We move all terms to the left:

-3(-7+2)-3u-(6(u-3)-4)=0

We add all the numbers together, and all the variables

-3u-(6(u-3)-4)-3(-5)=0

We add all the numbers together, and all the variables

-3u-(6(u-3)-4)+15=0



We calculate terms in parentheses: -(6(u-3)-4), so:

6(u-3)-4

We multiply parentheses

6u-18-4

We add all the numbers together, and all the variables

6u-22

Back to the equation:

-(6u-22)



We get rid of parentheses

-3u-6u+22+15=0

We add all the numbers together, and all the variables

-9u+37=0

We move all terms containing u to the left, all other terms to the right

-9u=-37

u=-37/-9

u=4+1/9

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