-3(-7-b)=1/3(b+31)

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Solution for -3(-7-b)=1/3(b+31) equation:



-3(-7-b)=1/3(b+31)
We move all terms to the left:
-3(-7-b)-(1/3(b+31))=0
Domain of the equation: 3(b+31))!=0
b∈R
We add all the numbers together, and all the variables
-3(-1b-7)-(1/3(b+31))=0
We multiply parentheses
3b-(1/3(b+31))+21=0
We multiply all the terms by the denominator
3b*3(b+31))-(1+21*3(b+31))=0
Wy multiply elements
9b^2(b+63b(b=0

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