-3(-7-b)=1/3(b+39)

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Solution for -3(-7-b)=1/3(b+39) equation: 



-3(-7-b)=1/3(b+39)

We move all terms to the left:

-3(-7-b)-(1/3(b+39))=0



Domain of the equation: 3(b+39))!=0

b∈R



We add all the numbers together, and all the variables

-3(-1b-7)-(1/3(b+39))=0

We multiply parentheses

3b-(1/3(b+39))+21=0

We multiply all the terms by the denominator


3b*3(b+39))-(1+21*3(b+39))=0

Wy multiply elements

9b^2(b+63b(b=0

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