-3(-7-b=1/3(b+39)

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Solution for -3(-7-b=1/3(b+39) equation: 



-3(-7-b=1/3(b+39)

We move all terms to the left:

-3(-7-b-(1/3(b+39))=0



Domain of the equation: 3(b+39))!=0

b∈R



We multiply all the terms by the denominator


-3(-7-b-(1=0

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