-3(-7-x)=1/3(x+39)

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Solution for -3(-7-x)=1/3(x+39) equation: 



-3(-7-x)=1/3(x+39)

We move all terms to the left:

-3(-7-x)-(1/3(x+39))=0



Domain of the equation: 3(x+39))!=0

x∈R



We add all the numbers together, and all the variables

-3(-1x-7)-(1/3(x+39))=0

We multiply parentheses

3x-(1/3(x+39))+21=0

We multiply all the terms by the denominator


3x*3(x+39))-(1+21*3(x+39))=0

Wy multiply elements

9x^2(x+63x(x=0

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