-3(-7u+2)-2u=7(u-3)-1

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Solution for -3(-7u+2)-2u=7(u-3)-1 equation: 



-3(-7u+2)-2u=7(u-3)-1

We move all terms to the left:

-3(-7u+2)-2u-(7(u-3)-1)=0

We add all the numbers together, and all the variables

-2u-3(-7u+2)-(7(u-3)-1)=0

We multiply parentheses

-2u+21u-(7(u-3)-1)-6=0



We calculate terms in parentheses: -(7(u-3)-1), so:

7(u-3)-1

We multiply parentheses

7u-21-1

We add all the numbers together, and all the variables

7u-22

Back to the equation:

-(7u-22)



We add all the numbers together, and all the variables

19u-(7u-22)-6=0

We get rid of parentheses

19u-7u+22-6=0

We add all the numbers together, and all the variables

12u+16=0

We move all terms containing u to the left, all other terms to the right

12u=-16

u=-16/12

u=-1+1/3

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