-3(-7y+1)-5y=7(y-2)-4

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Solution for -3(-7y+1)-5y=7(y-2)-4 equation: 



-3(-7y+1)-5y=7(y-2)-4

We move all terms to the left:

-3(-7y+1)-5y-(7(y-2)-4)=0

We add all the numbers together, and all the variables

-5y-3(-7y+1)-(7(y-2)-4)=0

We multiply parentheses

-5y+21y-(7(y-2)-4)-3=0



We calculate terms in parentheses: -(7(y-2)-4), so:

7(y-2)-4

We multiply parentheses

7y-14-4

We add all the numbers together, and all the variables

7y-18

Back to the equation:

-(7y-18)



We add all the numbers together, and all the variables

16y-(7y-18)-3=0

We get rid of parentheses

16y-7y+18-3=0

We add all the numbers together, and all the variables

9y+15=0

We move all terms containing y to the left, all other terms to the right

9y=-15

y=-15/9

y=-1+2/3

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