-3(-7y+2)-2y=3(y-1)-1

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Solution for -3(-7y+2)-2y=3(y-1)-1 equation: 



-3(-7y+2)-2y=3(y-1)-1

We move all terms to the left:

-3(-7y+2)-2y-(3(y-1)-1)=0

We add all the numbers together, and all the variables

-2y-3(-7y+2)-(3(y-1)-1)=0

We multiply parentheses

-2y+21y-(3(y-1)-1)-6=0



We calculate terms in parentheses: -(3(y-1)-1), so:

3(y-1)-1

We multiply parentheses

3y-3-1

We add all the numbers together, and all the variables

3y-4

Back to the equation:

-(3y-4)



We add all the numbers together, and all the variables

19y-(3y-4)-6=0

We get rid of parentheses

19y-3y+4-6=0

We add all the numbers together, and all the variables

16y-2=0

We move all terms containing y to the left, all other terms to the right

16y=2

y=2/16

y=1/8

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