-3(-7y+5)-7y=2(y-1)-5

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Solution for -3(-7y+5)-7y=2(y-1)-5 equation:



-3(-7y+5)-7y=2(y-1)-5
We move all terms to the left:
-3(-7y+5)-7y-(2(y-1)-5)=0
We add all the numbers together, and all the variables
-7y-3(-7y+5)-(2(y-1)-5)=0
We multiply parentheses
-7y+21y-(2(y-1)-5)-15=0
We calculate terms in parentheses: -(2(y-1)-5), so:
2(y-1)-5
We multiply parentheses
2y-2-5
We add all the numbers together, and all the variables
2y-7
Back to the equation:
-(2y-7)
We add all the numbers together, and all the variables
14y-(2y-7)-15=0
We get rid of parentheses
14y-2y+7-15=0
We add all the numbers together, and all the variables
12y-8=0
We move all terms containing y to the left, all other terms to the right
12y=8
y=8/12
y=2/3

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